What is the mass percentage of carbon in urea | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The molecular formula of urea is $NH_2CONH_2$.We know that the mass percentage of an element in a compound is given by:$	ext{Mass percentage} = \

Vedclass · Accepted Answer

$20.0$

Vedclass · Answer

(B) The molecular formula of urea is $NH_2CONH_2$.We know that the mass percentage of an element in a compound is given by:$	ext{Mass percentage} = \frac{	ext{Total mass of the element in one mole of compound}}{	ext{Molar mass of the compound}} 	imes 100$In one mole of urea $(NH_2CONH_2)$,there is $1$ mole of carbon atom.The molar mass of carbon is $12 \ g \ mol^{-1}$.The molar mass of urea is given as $60 \ g \ mol^{-1}$.Therefore,the mass percentage of carbon in urea $= \frac{12 \ g \ mol^{-1}}{60 \ g \ mol^{-1}} 	imes 100 = 20 \%$.Hence,option $B$ is correct.

What is the mass percentage of carbon in urea (in $\%$)? (molar mass of urea $= 60 \ g \ mol^{-1}$)

Similar Questions

An organic compound has the percentage of $C$ and $H$ in the ratio $6 : 1$ and the percentage of $C$ and $O$ in the ratio $3 : 4$. The compound is:

What is the mass of oxygen in $32.2 \ g$ of $Na_2SO_4 \cdot 10H_2O$ (in $g$)?

In an organic compound,the weight ratio of $C$,$H$,and $N$ atoms is $9 : 1 : 3.5$. If the molecular weight of the compound is $108$,what is its molecular formula?

An organic compound contains $69 \%$ carbon and $4.8 \%$ hydrogen,the remainder being oxygen. Calculate the masses of carbon dioxide and water produced when $0.20 \ g$ of this substance is subjected to complete combustion.

What is the percentage by mass of oxygen in $NaOH$? (Atomic mass of $Na=23 \ u, O=16 \ u, H=1 \ u$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module