How many electrons are needed to reduce N_2 t | vedclass

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Question

(D) The reduction of nitrogen gas $(N_2)$ to ammonia $(NH_3)$ involves the following balanced half-reaction:$N_2 + 6e^{-} + 6H^{+} \rightarrow 2NH_3$I

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(D) The reduction of nitrogen gas $(N_2)$ to ammonia $(NH_3)$ involves the following balanced half-reaction:$N_2 + 6e^{-} + 6H^{+} ightarrow 2NH_3$In this reaction, the oxidation state of nitrogen changes from $0$ in $N_2$ to $-3$ in $NH_3$.Since there are two nitrogen atoms, the total change in oxidation state is $2 	imes 3 = 6$.Therefore, $6$ electrons are required for the reduction process.

How many electrons are needed to reduce $N_2$ to $NH_3$?

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