How many isomers (cyclic and acyclic) are pos | vedclass

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(C) The degree of unsaturation $(DU)$ for $C_3H_6O$ is calculated as: $DU = C + 1 - \frac{H}{2} = 3 + 1 - \frac{6}{2} = 1$. This indicates the presenc

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(C) The degree of unsaturation $(DU)$ for $C_3H_6O$ is calculated as: $DU = C + 1 - \frac{H}{2} = 3 + 1 - \frac{6}{2} = 1$. This indicates the presence of either one double bond or one ring. Possible acyclic isomers: $1$. Propanal $(CH_3CH_2CHO)$ $2$. Propanone $(CH_3COCH_3)$ $3$. Allyl alcohol $(CH_2=CH-CH_2OH)$ $4$. $1$-propen$-1-$ol $(CH_3-CH=CH-OH)$ $5$. $2$-propen$-1-$ol $(CH_2=C(OH)-CH_3)$ $6$. Methoxyethene $(CH_3-O-CH=CH_2)$ Possible cyclic isomers: $7$. Cyclopropanol $8$. Methoxycyclopropane (Oxetane is not possible as it has $4$ atoms in ring,but $C_3H_6O$ can form $2$-methyloxirane or oxetane) $9$. $2$-methyloxirane (propylene oxide) $10$. Oxetane Wait,let us list them carefully: $(1)$ Propanal,$(2)$ Propanone,$(3)$ Allyl alcohol $(CH_2=CHCH_2OH)$,$(4)$ $1$-propen$-1-$ol $(CH_3CH=CHOH)$,$(5)$ $2$-propen$-1-$ol $(CH_2=C(OH)CH_3)$,$(6)$ Methoxyethene $(CH_3OCH=CH_2)$,$(7)$ Cyclopropanol,$(8)$ $2$-methyloxirane,$(9)$ Oxetane. Total isomers = $9$.

How many isomers (cyclic and acyclic) are possible for a compound with molecular formula $C_3H_6O$?

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