How many stereoisomers does the molecule CH_3 | vedclass

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(C) The molecule $CH_3-CH=CH-CH_2-CH(Br)-CH_3$ contains two stereogenic elements:$1$. $A$ carbon-carbon double bond $(CH=CH)$ which exhibits geometric

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$4$

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(C) The molecule $CH_3-CH=CH-CH_2-CH(Br)-CH_3$ contains two stereogenic elements:$1$. $A$ carbon-carbon double bond $(CH=CH)$ which exhibits geometrical isomerism (cis/trans).$2$. $A$ chiral carbon atom at the $C-5$ position (attached to $-H, -Br, -CH_3, -CH_2-CH=CH-CH_3$ groups),which exhibits optical isomerism.Since there are $n = 2$ stereogenic centers and they are not identical,the total number of stereoisomers is given by the formula $2^n$.Total stereoisomers $= 2^2 = 4$.

How many stereoisomers does the molecule $CH_3-CH=CH-CH_2-CH(Br)-CH_3$ have?

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