How many monochloro structural isomers are ex | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The structure of isopentane is $CH_3-CH(CH_3)-CH_2-CH_3$.There are $4$ distinct types of hydrogen atoms in isopentane:$1$. Primary hydrogens on th

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The structure of isopentane is $CH_3-CH(CH_3)-CH_2-CH_3$.There are $4$ distinct types of hydrogen atoms in isopentane:$1$. Primary hydrogens on the terminal $CH_3$ group attached to the $CH$ group.$2$. Tertiary hydrogen on the $CH$ group.$3$. Secondary hydrogens on the $CH_2$ group.$4$. Primary hydrogens on the terminal $CH_3$ group attached to the $CH_2$ group.Since there are $4$ different types of hydrogen atoms,replacing any one of them with a chlorine atom will result in $4$ different monochloro structural isomers.Therefore,the correct answer is $4$.

How many monochloro structural isomers are expected to be formed on free radical monochlorination of isopentane?

Similar Questions

Considering the following reaction,what is the structure of the major product '$X$'?
$H_3C-CH(D)-CH(CH_3)-CH_3 + Br^\bullet \to 'X' + HBr$

An alkane $(Y)$ requires $8$ moles of oxygen for complete combustion and on chlorination with $Cl_2/h\nu$, $(Y)$ gives only one monochlorinated product $(Z)$. The total number of primary carbon atoms in $(Y)$ is . . . . . . .

The product $(A)$ of the above reaction is:

$Br^{\bullet}$ will abstract which of the hydrogen most readily?

Complete the following reactions:
$(i)$ Liberation of dihydrogen gas from methane.
(ii) Oxidation of $2$-methylpropane.

Vedclass Test Series

Exam Paper Generator

Online Exam Module