How many numbers of 6 digits can be formed fr | vedclass

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(C) The given number is $112233$,which consists of $6$ digits in total.The digits are $1, 1, 2, 2, 3, 3$.Here,the digit $1$ repeats $2$ times,the digi

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$90$

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(C) The given number is $112233$,which consists of $6$ digits in total.The digits are $1, 1, 2, 2, 3, 3$.Here,the digit $1$ repeats $2$ times,the digit $2$ repeats $2$ times,and the digit $3$ repeats $2$ times.The number of ways to arrange these $6$ digits is given by the formula for permutations of a multiset:$	ext{Number of ways} = \frac{n!}{n_1! \cdot n_2! \cdot n_3!}$Substituting the values: $n = 6$,$n_1 = 2$,$n_2 = 2$,$n_3 = 2$.$	ext{Number of ways} = \frac{6!}{2! \cdot 2! \cdot 2!} = \frac{720}{2 \cdot 2 \cdot 2} = \frac{720}{8} = 90$.Thus,$90$ such numbers can be formed.

How many numbers of $6$ digits can be formed from the digits of the number $112233$?

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