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(D) The compound is $2$-methylbutane,$(CH_3)_2CH-CH_2-CH_3$. Monochlorination can occur at four different types of hydrogen atoms:$1$. Substitution at

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$6$

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(D) The compound is $2$-methylbutane,$(CH_3)_2CH-CH_2-CH_3$. Monochlorination can occur at four different types of hydrogen atoms:$1$. Substitution at the $C_1$ position (terminal methyl group): $ClCH_2-CH(CH_3)-CH_2-CH_3$. This product has a chiral center,so it exists as a pair of enantiomers ($2$ products).$2$. Substitution at the $C_2$ position: $CH_3-CCl(CH_3)-CH_2-CH_3$. This is an achiral product ($1$ product).$3$. Substitution at the $C_3$ position: $CH_3-CH(CH_3)-CHCl-CH_3$. This product has a chiral center,so it exists as a pair of enantiomers ($2$ products).$4$. Substitution at the $C_4$ position: $CH_3-CH(CH_3)-CH_2-CH_2Cl$. This is an achiral product ($1$ product).Total number of products = $2 + 1 + 2 + 1 = 6$.

How many products (including stereoisomers) are expected from the monochlorination of the following compound? (Structure: $(CH_3)_2CH-CH_2-CH_3$)

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