How many products will be formed in the reaction shown below?
$CH_3-CH_2-C(CH_3)=C(CH_3)-CH_2-CH_3 + HBr \xrightarrow{R_2O_2} \text{Products}$

The product of the reaction between propene and $HBr$ in the presence of a peroxide is:

Aqueous solution of sodium salt of $2-$methylbutanedioic acid on Kolbe's electrolysis gives:

Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A)$: Cis form of alkene is found to be more polar than the trans form.
Reason $(R)$: Dipole moment of trans isomer of $2$-butene is zero.
In the light of the above statements,choose the correct answer from the options given below:

Which of the following is formed when propene is heated with chlorine at high temperature?

What will be the product of the reaction: $CH_3-CH=C(CH_3)_2 + HCl \to$ ?