What will be the product of the reaction: CH_ | vedclass

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Question

(A) The reaction follows $Markovnikov's$ rule,where the electrophile $H^+$ adds to the carbon atom with more hydrogen atoms,and the nucleophile $Cl^-$

Vedclass · Accepted Answer

$CH_3-CH_2-C(Cl)(CH_3)_2$

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(A) The reaction follows $Markovnikov's$ rule,where the electrophile $H^+$ adds to the carbon atom with more hydrogen atoms,and the nucleophile $Cl^-$ adds to the more substituted carbon atom (forming a more stable carbocation).$1$. The reactant is $2-methylbut-2-ene$.$2$. The addition of $HCl$ leads to the formation of $2-chloro-2-methylbutane$ as the major product.$3$. The structure is $CH_3-CH_2-C(Cl)(CH_3)_2$.

What will be the product of the reaction: $CH_3-CH=C(CH_3)_2 + HCl \to$ ?

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