How many times more intense is 90, dB sound t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let $I$ represent the intensity of sound.The loudness of sound is given by the formula: $L = 10 \log_{10} \left( \frac{I}{I_0} \right)$.For two di

Vedclass · Accepted Answer

$10^5$

Vedclass · Answer

(D) Let $I$ represent the intensity of sound.The loudness of sound is given by the formula: $L = 10 \log_{10} \left( \frac{I}{I_0} \right)$.For two different sound levels $L_1$ and $L_2$ with intensities $I_1$ and $I_2$,the difference in loudness is:$L_2 - L_1 = 10 \log_{10} \left( \frac{I_2}{I_1} \right)$.Given $L_2 = 90\, dB$ and $L_1 = 40\, dB$:$90 - 40 = 10 \log_{10} \left( \frac{I_2}{I_1} \right)$.$50 = 10 \log_{10} \left( \frac{I_2}{I_1} \right)$.$5 = \log_{10} \left( \frac{I_2}{I_1} \right)$.Therefore,$\frac{I_2}{I_1} = 10^5$.

How many times more intense is $90\, dB$ sound than $40\, dB$ sound?

Similar Questions

$A$ musical scale is constructed by providing intermediate frequencies between a note and its octave which:

The intensity of sound during the festival season increased by $100$ times. This could imply a decibel $(dB)$ level rise from

In the musical octave 'Sa','Re','Ga',which of the following statements is correct regarding their frequencies?

The 'Loudness' and 'Pitch' of sound respectively are the human perception to

$A$ sound absorber attenuates (decreases) the sound level by $20 \ dB$. The intensity decreases by a factor of

Vedclass Test Series

Exam Paper Generator

Online Exam Module