What is the order of magnitude of the dimensi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the alpha-particle scattering experiment,Rutherford observed that alpha particles were deflected by the nucleus.By calculating the distance of

Vedclass · Accepted Answer

$10^{-15} \ m$

Vedclass · Answer

(B) In the alpha-particle scattering experiment,Rutherford observed that alpha particles were deflected by the nucleus.By calculating the distance of closest approach,he estimated the size of the nucleus.The distance of closest approach $r_0$ is given by the formula $r_0 = \frac{1}{4\pi\epsilon_0} \frac{2Ze^2}{K}$,where $K$ is the kinetic energy of the alpha particle.Based on his experimental results,Rutherford concluded that the radius of the nucleus is of the order of $10^{-15} \ m$ (or $1 \ fm$).

What is the order of magnitude of the dimension of the nucleus as estimated by Rutherford?

Similar Questions

Given below are two statements $:$ one is labelled as Assertion $(A)$ and other is labelled as Reason $(R).$
Assertion $(A) :$ Neutrons penetrate matter more readily as compared to protons.
Reason $(R) :$ Neutrons are slightly more massive than protons.

The strongest force in nature is

Nuclear forces are

The nuclear radius is given by $R = r_0 A^{1/3}$,where $r_0$ is a constant and $A$ is the atomic mass number. Then,the nuclear mass density of $^{238}U$ is

In the atomic scale,the weakest force in nature is

Vedclass Test Series

Exam Paper Generator

Online Exam Module