The nuclear radius is given by R = r_0 A^{1/3 | vedclass

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(C) The nuclear radius is given by $R = r_0 A^{1/3}$.The volume of the nucleus is $V = \frac{4}{3} \pi R^3 = \frac{4}{3} \pi (r_0 A^{1/3})^3 = \frac{4

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same as that of $^{119}Sn$

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(C) The nuclear radius is given by $R = r_0 A^{1/3}$.The volume of the nucleus is $V = \frac{4}{3} \pi R^3 = \frac{4}{3} \pi (r_0 A^{1/3})^3 = \frac{4}{3} \pi r_0^3 A$.The nuclear mass is approximately $M = A 	imes m_p$,where $m_p$ is the mass of a nucleon (proton or neutron).The nuclear density $ho$ is given by $ho = \frac{M}{V} = \frac{A \cdot m_p}{\frac{4}{3} \pi r_0^3 A} = \frac{3 m_p}{4 \pi r_0^3}$.Since $m_p$ and $r_0$ are constants,the nuclear density $ho$ is independent of the mass number $A$.Therefore,the nuclear mass density of $^{238}U$ is the same as that of $^{119}Sn$.

The nuclear radius is given by $R = r_0 A^{1/3}$,where $r_0$ is a constant and $A$ is the atomic mass number. Then,the nuclear mass density of $^{238}U$ is

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