How will you convert:
$(i)$ Benzene into aniline
$(ii)$ Benzene into $N,N$-dimethylaniline
$(iii)$ $Cl-(CH_2)_4-Cl$ into hexane-$1,6$-diamine?
$(i)$ Benzene into aniline
$(ii)$ Benzene into $N,N$-dimethylaniline
$(iii)$ $Cl-(CH_2)_4-Cl$ into hexane-$1,6$-diamine?
(N/A) $(i)$ Benzene $\xrightarrow{Conc. HNO_3 / Conc. H_2SO_4}$ Nitrobenzene $\xrightarrow{H_2/Pd, Ethanol}$ Aniline.
$(ii)$ Benzene $\xrightarrow{Conc. HNO_3 / Conc. H_2SO_4}$ Nitrobenzene $\xrightarrow{H_2/Pd, Ethanol}$ Aniline $\xrightarrow{2CH_3Cl}$ $N,N$-Dimethylaniline.
$(iii)$ $Cl-(CH_2)_4-Cl$ $\xrightarrow{Ethanolic NaCN}$ $NC-(CH_2)_4-CN$ $\xrightarrow{H_2/Ni}$ $H_2N-(CH_2)_6-NH_2$ (Hexane-$1,6$-diamine).
$(ii)$ Benzene $\xrightarrow{Conc. HNO_3 / Conc. H_2SO_4}$ Nitrobenzene $\xrightarrow{H_2/Pd, Ethanol}$ Aniline $\xrightarrow{2CH_3Cl}$ $N,N$-Dimethylaniline.
$(iii)$ $Cl-(CH_2)_4-Cl$ $\xrightarrow{Ethanolic NaCN}$ $NC-(CH_2)_4-CN$ $\xrightarrow{H_2/Ni}$ $H_2N-(CH_2)_6-NH_2$ (Hexane-$1,6$-diamine).
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Similar Questions
Match List-$I$ with List-$II$.
List-$I$ (Mixture of Compounds)
List-$II$ (Reagent used to distinguish)
$A$. Diethyl amine + Ethyl amine
$I$. Bromine water
$B$. Acetaldehyde + Acetone
$II$. $CHCl_3 + KOH, \Delta$
$C$. Ethanol + Phenol
$III$. Neutral $FeCl_3$
$D$. Benzoic acid + Cinnamic acid
$IV$. Ammonical silver nitrate
| List-$I$ (Mixture of Compounds) | List-$II$ (Reagent used to distinguish) |
|---|---|
| $A$. Diethyl amine + Ethyl amine | $I$. Bromine water |
| $B$. Acetaldehyde + Acetone | $II$. $CHCl_3 + KOH, \Delta$ |
| $C$. Ethanol + Phenol | $III$. Neutral $FeCl_3$ |
| $D$. Benzoic acid + Cinnamic acid | $IV$. Ammonical silver nitrate |
DifficultJEE MAIN 2026
View SolutionEthylamine can be obtained by the:
Difficult
View SolutionIdentify $C$ in the following reaction sequence:
$Cyclohexanone$ $\xrightarrow[\text{Alkaline medium}]{HCN} A$ $\xrightarrow{LiAlH_4} B$ $\xrightarrow{NaNO_2/HCl} C$
$Cyclohexanone$ $\xrightarrow[\text{Alkaline medium}]{HCN} A$ $\xrightarrow{LiAlH_4} B$ $\xrightarrow{NaNO_2/HCl} C$
Difficult
View SolutionThe most reactive amine towards dilute hydrochloric acid is ..........
Medium
View SolutionGive a plausible explanation for each of the following:
$(i)$ Why are amines less acidic than alcohols of comparable molecular masses?
$(ii)$ Why do primary amines have higher boiling points than tertiary amines?
$(iii)$ Why are aliphatic amines stronger bases than aromatic amines?
$(i)$ Why are amines less acidic than alcohols of comparable molecular masses?
$(ii)$ Why do primary amines have higher boiling points than tertiary amines?
$(iii)$ Why are aliphatic amines stronger bases than aromatic amines?
Medium
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