Match List-I with List-II.

List- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$(A)$. Diethyl amine (secondary amine) and Ethyl amine (primary amine) can be distinguished using the Carbylamine test $(CHCl_3 + KOH, \Delta)$; only

Vedclass · Accepted Answer

$A-II, B-IV, C-III, D-I$

Vedclass · Answer

$(A)$. Diethyl amine (secondary amine) and Ethyl amine (primary amine) can be distinguished using the Carbylamine test $(CHCl_3 + KOH, \Delta)$; only primary amines react to form an isocyanide with a foul smell $(A-II)$.
$B$. Acetaldehyde (aldehyde) and Acetone (ketone) can be distinguished using Tollens' test (Ammonical silver nitrate); only acetaldehyde reacts to form a silver mirror $(B-IV)$.
$C$. Ethanol and Phenol can be distinguished using Neutral $FeCl_3$; phenol gives a characteristic violet color with neutral $FeCl_3$ $(C-III)$.
$D$. Benzoic acid and Cinnamic acid can be distinguished using Bromine water; cinnamic acid contains a carbon-carbon double bond (unsaturation) and decolorizes bromine water, whereas benzoic acid does not $(D-I)$.
Therefore, the correct matching is $A-II, B-IV, C-III, D-I$.

List-$I$ (Mixture of Compounds)	List-$II$ (Reagent used to distinguish)
$A$. Diethyl amine + Ethyl amine	$I$. Bromine water
$B$. Acetaldehyde + Acetone	$II$. $CHCl_3 + KOH, \Delta$
$C$. Ethanol + Phenol	$III$. Neutral $FeCl_3$
$D$. Benzoic acid + Cinnamic acid	$IV$. Ammonical silver nitrate

Similar Questions

The major products $P$ and $Q$ formed in the following reactions of benzonitrile are

Which of the following statements is correct?

In a reaction of aniline,a coloured product $C$ was obtained as shown below:
$A$ $\xrightarrow{NaNO_2/HCl} B$ $\xrightarrow{N,N-dimethylaniline, \text{cold}} C$
The structure of $C$ would be:

Product $(E)$ is

Consider the following sequence of reactions. Assuming that the reaction proceeds to completion, then $137 \ mg$ of $4-$nitrotoluene will produce . . . . . . $mg$ of $B$. (Given molar mass in $g \ mol^{-1}: H = 1, C = 12, N = 14, O = 16, Br = 80$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module