Determine the hybridization of the C_3 and C_ | vedclass

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Question

(A) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority,so the carbon of the $-COOH$ group is $

Vedclass · Accepted Answer

$sp^2, sp^2$

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(A) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority,so the carbon of the $-COOH$ group is $C_1$.$2$. Number the chain: $C_1$ (carboxyl carbon),$C_2$ (alpha carbon),$C_3$ (carbon with double bond),$C_4$ (carbon with double bond),$C_5$ (chiral center),$C_6$ (carbon with double bond).$3$. Analyze $C_3$: The $C_3$ atom is part of a carbon-carbon double bond $(C=C)$,meaning it is bonded to three atoms (one $C$,one $C$,one $H$). Thus,its hybridization is $sp^2$.$4$. Analyze $C_6$: The $C_6$ atom is part of a terminal carbon-carbon double bond $(CH=CH_2)$,meaning it is bonded to three atoms (one $C$,two $H$). Thus,its hybridization is $sp^2$.$5$. Conclusion: Both $C_3$ and $C_6$ are $sp^2$ hybridized.

Determine the hybridization of the $C_3$ and $C_6$ carbon atoms in the given structure,respectively. (Numbering starts from the left end of the longest chain containing the principal functional group).

Similar Questions

Which of the following compounds contains carbon atoms with both $sp$ and $sp^2$ hybridization?

Determine the hybridization of the carbon atoms in the following compounds:
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$(c)$ $HC \equiv C-C \equiv CH$
$(d)$ $H_2C=C=C=CH_2$
$(e)$ Buta$-1,3-$diene (as shown in the figure)

What is the hybridization state of carbon atoms $1, 2, 3,$ and $4$ in the given reaction?

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Which of the following represents the given mode of hybridisation $sp^2-sp^2-sp-sp$ from left to right?

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