What is the hybridization of the central I at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the hybridization of the triiodide ion $(I_3^-)$,we use the formula:$	ext{Number of Hybrid Orbitals} = \frac{1}{2} 	imes (V + M - C

Vedclass · Accepted Answer

$sp^3d$

Vedclass · Answer

(D) To determine the hybridization of the triiodide ion $(I_3^-)$,we use the formula:$	ext{Number of Hybrid Orbitals} = \frac{1}{2} 	imes (V + M - C + A)$Where:$V = 	ext{Number of valence electrons of the central atom} = 7$$M = 	ext{Number of monovalent atoms attached} = 2$$C = 	ext{Cationic charge} = 0$$A = 	ext{Anionic charge} = 1$Substituting the values:$	ext{Number of Hybrid Orbitals} = \frac{1}{2} 	imes (7 + 2 - 0 + 1) = \frac{10}{2} = 5$$A$ hybridization number of $5$ corresponds to $sp^3d$ hybridization.

What is the hybridization of the central $I$ atom in the $I_3^-$ ion?

Similar Questions

Which of the following is an incorrect relation based on Bent's rule?

What is meant by hybridisation of atomic orbitals? Describe the shapes of $sp$,$sp^{2}$,$sp^{3}$ hybrid orbitals.

If the dipole moment of an $MX_3$ molecule is zero,then the orbitals used by $M$ $(atomic\ number < 21)$ in sigma bonding are ....

What is the proportion of $s$-character in $sp^3$,$sp^2$,and $sp$ hybrid orbitals? What is the order of electronegativity in it?

What is the hybridization of the central atom in $SiF_6^{2-}$ and $[Sn(OH)_6]^{2-}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module