$A$ hydrogen atom is excited from the ground state to a state with principal quantum number $n = 4$. The number of spectral lines emitted in the emission spectrum is:

  • A
    $3$
  • B
    $6$
  • C
    $5$
  • D
    $2$

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Similar Questions

Match List $I$ with List $II$.
List $I$ (Spectral Lines of Hydrogen for transitions from) List $II$ (Wavelengths $(nm)$)
$A$. $n_2=3$ to $n_1=2$ $I$. $410.2$
$B$. $n_2=4$ to $n_1=2$ $II$. $434.1$
$C$. $n_2=5$ to $n_1=2$ $III$. $656.3$
$D$. $n_2=6$ to $n_1=2$ $IV$. $486.1$

Choose the correct answer from the options given below:

In the spectrum of hydrogen,the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is

The shortest wavelength in the Lyman series is $912 \ \text{Å}$. Then, the longest wavelength in the series must be (in $\text{Å}$)

If the first line of Lyman series has a wavelength $1215.4 \text{ Å}$, the first line of Balmer series is approximately (in $\text{ Å}$)

The longest wavelength associated with the Paschen series is: (Given $R_H = 1.097 \times 10^7 \ m^{-1}$)

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