Identify the structure of B in the following | vedclass

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(B) $1$. The starting material is $2,6-	ext{dimethylcyclohexane-1,4-dione}$.$2$. Reaction with $	ext{ethane-1,2-diol}$ in the presence of $H^+$ is a

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(B) $1$. The starting material is $2,6-	ext{dimethylcyclohexane-1,4-dione}$.$2$. Reaction with $	ext{ethane-1,2-diol}$ in the presence of $H^+$ is a protection reaction. The more reactive ketone (less sterically hindered) is protected as a cyclic acetal. In $2,6-	ext{dimethylcyclohexane-1,4-dione}$,the $C_4$ ketone is less hindered than the $C_1$ ketone (which is flanked by two methyl groups). Thus,$A$ is $2,6-	ext{dimethyl-4,4-(ethylenedioxy)cyclohexan-1-one}$.$3$. Treatment with $LiAlH_4$ reduces the remaining ketone at $C_1$ to a secondary alcohol.$4$. Subsequent acid hydrolysis $(H_3O^+)$ removes the acetal protecting group at $C_4$,regenerating the ketone.$5$. The final product $B$ is $4-	ext{hydroxy-2,6-dimethylcyclohexan-1-one}$ (or its isomer depending on stereochemistry,but the connectivity is $4-	ext{hydroxy-2,6-dimethylcyclohexan-1-one}$).

Column-$I$ (Reactions)	Column-$II$ (Reagents)
$(A).$ Benzophenone $\to$ Diphenylmethane	$(1).$ $LiAlH_4$
$(B).$ Benzaldehyde $\to$ $1-$Phenylethanol	$(2).$ $DiBAL-H$
$(C).$ Cyclohexanone $\to$ Cyclohexanol	$(3).$ $Zn(Hg) / \text{Conc. } HCl$
$(D).$ Phenyl benzoate $\to$ Benzaldehyde	$(4).$ $CH_3MgBr$

Identify the structure of $B$ in the following reaction sequence:
$2,6-\text{dimethylcyclohexane-1,4-dione} + \text{ethane-1,2-diol}$ $\xrightarrow{H^+} A$ $\xrightarrow[2. H_3O^+]{1. LiAlH_4} B$

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Identify the structure of $B$ in the following reaction sequence:$2,6-\text{dimethylcyclohexane-1,4-dione} + \text{ethane-1,2-diol}$ $\xrightarrow{H^+} A$ $\xrightarrow[2. H_3O^+]{1. LiAlH_4} B$