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(B) The given reaction is a cross-Cannizzaro reaction between benzaldehyde $(C_6H_5CHO)$ and formaldehyde $(HCHO)$.In a cross-Cannizzaro reaction,the

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$	ext{Benzyl alcohol and Formic acid}$

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(B) The given reaction is a cross-Cannizzaro reaction between benzaldehyde $(C_6H_5CHO)$ and formaldehyde $(HCHO)$.In a cross-Cannizzaro reaction,the more reactive carbonyl compound (formaldehyde) is oxidized to the corresponding acid (formate ion,which gives formic acid $HCOOH$ upon acidification),and the less reactive carbonyl compound (benzaldehyde) is reduced to the corresponding alcohol (benzyl alcohol,$C_6H_5CH_2OH$).Therefore,the products are benzyl alcohol and formic acid.

The major products of the following reaction are:

Similar Questions

Which of the following is most reactive towards the addition reaction of hydrogen cyanide to form the corresponding cyanohydrin?

$2Ph-CHO \xrightarrow{OH^-} Ph-CH_2OH + PhCOO^-$
Which is the slowest step in the above Cannizzaro reaction?

Arrange the following compounds in the increasing order of their reactivity towards the nucleophilic addition of $HCN$:
$1. HCHO$
$2. CH_3COCH_3$
$3. PhCOCH_3$
$4. PhCOPh$

Give the best conditions for this transformation:

What is $C$ in the following reaction sequence?

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