2Ph-CHO xrightarrow{OH^-} Ph-CH_2OH + PhCOO^- | vedclass

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(B) The mechanism of the Cannizzaro reaction involves the nucleophilic attack of $OH^-$ on the carbonyl carbon to form a dihydroxyalkoxide intermediat

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Hydride ion transfer to the carbonyl group

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(B) The mechanism of the Cannizzaro reaction involves the nucleophilic attack of $OH^-$ on the carbonyl carbon to form a dihydroxyalkoxide intermediate.This is followed by the transfer of a hydride ion $(H^-)$ from the intermediate to another molecule of aldehyde.The hydride shift is the rate-determining step (slow step) of the reaction.Finally,a rapid proton exchange occurs to form the alcohol and carboxylate ion.

Test	$C$	$D$
Ceric ammonium nitrate Test	Positive	Positive
Lucas Test	Turbidity obtained after five minutes	Turbidity obtained immediately
Iodoform Test	Positive	Negative

$2Ph-CHO \xrightarrow{OH^-} Ph-CH_2OH + PhCOO^-$
Which is the slowest step in the above Cannizzaro reaction?

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$2Ph-CHO \xrightarrow{OH^-} Ph-CH_2OH + PhCOO^-$Which is the slowest step in the above Cannizzaro reaction?