Two compounds A and B with the same molecular | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) is propanal $(CH_{3}CH_{2}CHO)$. Reaction with $CH_{3}MgBr$ gives butan$-2-$ol $(CH_{3}CH_{2}CH(OH)CH_{3})$ as $C$.Butan$-2-$ol is a $2^{\circ}$ a

Vedclass · Accepted Answer

$C = CH_{3}CH_{2}CH(OH)CH_{3}$,$D = CH_{3}C(CH_{3})(OH)CH_{3}$

Vedclass · Answer

(C) is propanal $(CH_{3}CH_{2}CHO)$. Reaction with $CH_{3}MgBr$ gives butan$-2-$ol $(CH_{3}CH_{2}CH(OH)CH_{3})$ as $C$.Butan$-2-$ol is a $2^{\circ}$ alcohol,gives positive Iodoform test,and Lucas test turbidity in $5$ minutes.$B$ is acetone $(CH_{3}COCH_{3})$. Reaction with $CH_{3}MgBr$ gives $2$-methylpropan$-2-$ol $(CH_{3}C(CH_{3})(OH)CH_{3})$ as $D$.$2$-methylpropan$-2-$ol is a $3^{\circ}$ alcohol,gives immediate turbidity with Lucas reagent,and negative Iodoform test.Thus,$C$ is $CH_{3}CH_{2}CH(OH)CH_{3}$ and $D$ is $CH_{3}C(CH_{3})(OH)CH_{3}$.

Test	$C$	$D$
Ceric ammonium nitrate Test	Positive	Positive
Lucas Test	Turbidity obtained after five minutes	Turbidity obtained immediately
Iodoform Test	Positive	Negative

Similar Questions

Which of the following will not give the iodoform test?

For the reduction of ketones to hydrocarbon,the appropriate agent is

The major product in the following reaction sequence is

$CH_3-CO-CH_2-COOCH_3$ $\xrightarrow[H_2O]{H^{+}} A$ $\xrightarrow{\Delta} B$ $\xrightarrow{HCN} C$. What are $B$ and $C$?

Fehling's solution '$A$' is

Vedclass Test Series

Exam Paper Generator

Online Exam Module