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(A) $Step \ 1$: Cyclohexanone reacts with $EtMgBr$ (Grignard reagent) followed by hydrolysis $(H_2O)$ to form $1$-ethylcyclohexanol.$Step \ 2$: Dehydr

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$1-$bromo$-1-$ethylcyclohexane

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(A) $Step \ 1$: Cyclohexanone reacts with $EtMgBr$ (Grignard reagent) followed by hydrolysis $(H_2O)$ to form $1$-ethylcyclohexanol.$Step \ 2$: Dehydration of $1$-ethylcyclohexanol in the presence of $20\% \ H_3PO_4$ yields ethylidenecyclohexane as the major alkene product.$Step \ 3$: Addition of $HBr$ to ethylidenecyclohexane follows Markovnikov's rule,where the proton adds to the terminal carbon of the double bond and the bromide ion adds to the more substituted carbon,resulting in $1$-bromo-$1$-ethylcyclohexane as the final product $(P)$.

The major product in the following reaction sequence is

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In the following reaction sequence,the product $D$ is:
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