Identify the correct decreasing order of stab | vedclass

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(D) The stability of coordination complexes formed by divalent metal ions with the same ligand generally follows the Irving-Williams series. According

Vedclass · Accepted Answer

$Cu^{2+} > Cd^{2+} > Mn^{2+}$

Vedclass · Answer

(D) The stability of coordination complexes formed by divalent metal ions with the same ligand generally follows the Irving-Williams series. According to the Irving-Williams series,the stability of complexes increases with the decrease in ionic radius and increase in the charge-to-size ratio. For the given ions,the order of stability is $Mn^{2+} However,the question asks for the decreasing order of stability. Comparing the given options,$Cu^{2+}$ is the most stable due to its smaller ionic radius and higher crystal field stabilization energy compared to $Mn^{2+}$ and $Cd^{2+}$. Thus,the correct decreasing order is $Cu^{2+} > Cd^{2+} > Mn^{2+}$.

Identify the correct decreasing order of stability of complexes formed by divalent metal ions with the same ligand.

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