Identify the correct trend given below.
(Atomic No. $= Ti : 22, Cr : 24$ and $Mo : 42$)

  • A
    $\Delta _0$ of $[Cr(H_2O)_6]^{2+} > [Mo(H_2O)_6]^{2+}$ and $\Delta _0$ of $[Ti(H_2O)_6]^{3+} > [Ti(H_2O)_6]^{2+}$
  • B
    $\Delta _0$ of $[Cr(H_2O)_6]^{2+} > [Mo(H_2O)_6]^{2+}$ and $\Delta _0$ of $[Ti(H_2O)_6]^{3+} < [Ti(H_2O)_6]^{2+}$
  • C
    $\Delta _0$ of $[Cr(H_2O)_6]^{2+} < [Mo(H_2O)_6]^{2+}$ and $\Delta _0$ of $[Ti(H_2O)_6]^{3+} > [Ti(H_2O)_6]^{2+}$
  • D
    $\Delta _0$ of $[Cr(H_2O)_6]^{2+} < [Mo(H_2O)_6]^{2+}$ and $\Delta _0$ of $[Ti(H_2O)_6]^{3+} < [Ti(H_2O)_6]^{2+}$

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