On what factors does the crystal field splitting in an octahedral complex depend?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The crystal field splitting $\Delta_{o}$ depends on the following factors:
$(i)$ Charge (oxidation state) of the metal ion: $A$ higher charge on the metal ion results in greater crystal field splitting.
$(ii)$ Strength of the ligands: Strong ligands produce strong fields,causing larger splitting of $d$-orbitals,which increases the crystal field splitting. Weak ligands result in smaller crystal field splitting.
The strength of ligands is determined experimentally based on the absorption of light by complexes with different ligands. When these ligands are arranged in a series in increasing order of field strength,it is known as the spectrochemical series:
$I^{-} < Br^{-} < SCN^{-} < Cl^{-} < S^{2-} < F^{-} < OH^{-} < C_{2}O_{4}^{2-} < H_{2}O < NCS^{-} < edta^{4-} < NH_{3} < en < CN^{-} < CO$

Explore More

Similar Questions

The $CFSE$ for $[CoCl_6]^{4-}$ complex is $18000 \ cm^{-1}$. The $\Delta_t$ for $[CoCl_4]^{2-}$ will be ........... $cm^{-1}$.

Which of the following are true about the energy of the given d-orbitals of a tetrahedral complex?
$A$. $d_{xy} = d_{xz} > d_{x^2-y^2}$
$B$. $d_{xy} = d_{yz} > d_{z^2}$
$C$. $d_{x^2-y^2} > d_{z^2} > d_{xz}$
$D$. $d_{x^2-y^2} = d_{z^2}$
Choose the correct answer from the given below:

Explain crystal field splitting in tetrahedral complexes.

Correct increasing order for the wavelength of absorption in the visible region for the complexes of $Co^{3+}$ is :

The correct order of energy of absorption for the following metal complexes is
$A: [Ni(en)_3]^{2+}, B: [Ni(NH_3)_6]^{2+}, C: [Ni(H_2O)_6]^{2+}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo