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(A) The energy of absorption is directly proportional to the crystal field splitting energy $(\Delta_o)$.According to the spectrochemical series,the f

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$C < B < A$

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(A) The energy of absorption is directly proportional to the crystal field splitting energy $(\Delta_o)$.According to the spectrochemical series,the field strength of the ligands is $H_2O Since the metal ion $(Ni^{2+})$ is the same in all complexes,the splitting energy depends on the ligand strength.Therefore,the order of splitting energy (and thus energy of absorption) is $[Ni(H_2O)_6]^{2+} < [Ni(NH_3)_6]^{2+} < [Ni(en)_3]^{2+}$,which corresponds to $C < B < A$.

$I$. $NCS^{-}$	$II$. $S^{2-}$
$III$. $en$	$IV$. $SCN^{-}$

The correct order of energy of absorption for the following metal complexes is
$A: [Ni(en)_3]^{2+}, B: [Ni(NH_3)_6]^{2+}, C: [Ni(H_2O)_6]^{2+}$

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The correct order of energy of absorption for the following metal complexes is$A: [Ni(en)_3]^{2+}, B: [Ni(NH_3)_6]^{2+}, C: [Ni(H_2O)_6]^{2+}$