The correct order of decreasing field strengt | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The crystal field splitting,$\Delta_0$,depends upon the field produced by the ligand and the charge on the metal ion. Ligands are arranged in a sp

Vedclass · Accepted Answer

$III > I > IV > II$

Vedclass · Answer

(C) The crystal field splitting,$\Delta_0$,depends upon the field produced by the ligand and the charge on the metal ion. Ligands are arranged in a spectrochemical series based on their field strength. The order of increasing field strength is: $I^{-} Comparing the given ligands: $III$ $(en)$ is a strong field ligand. $I$ $(NCS^{-})$ is stronger than $IV$ $(SCN^{-})$. $II$ $(S^{2-})$ is a weak field ligand. Thus,the decreasing order of field strength is $III > I > IV > II$.

$I$. $NCS^{-}$	$II$. $S^{2-}$
$III$. $en$	$IV$. $SCN^{-}$

The correct order of decreasing field strength of the below given ligands is
$I$. $NCS^{-}$ $II$. $S^{2-}$
$III$. $en$ $IV$. $SCN^{-}$

Similar Questions

Write the correct order of wavelength of absorption in the visible region for the following complexes:

Crystal field stabilization energy for high spin $d^4$ octahedral complex is

Which of the following is correct related to the colours of $TiCl_3$ $(X)$ and $[Ti(H_2O)_6]Cl_3$ $(Y)$?

Arrange the following complex ions in increasing order of crystal field splitting energy $(\Delta_{0}):$ $[Cr(Cl)_{6}]^{3-}, [Cr(CN)_{6}]^{3-}, [Cr(NH_{3})_{6}]^{3+}$

In which of the following coordination entities the magnitude of $\Delta_o$ ($CFSE$ in octahedral field) will be maximum? (Atomic Number of $Co = 27$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The correct order of decreasing field strength of the below given ligands is$I$. $NCS^{-}$$II$. $S^{2-}$$III$. $en$$IV$. $SCN^{-}$