Identify the formula of the coordination comp | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. The central metal ion is $Pt$ with an oxidation state of $+4$.
$2$. The ligand $ethylenediamine$ $(en)$ is a neutral bidentate ligand. Since

Vedclass · Accepted Answer

$[Pt(en)_2(SCN)_2]^{2+}$

Vedclass · Answer

(B) $1$. The central metal ion is $Pt$ with an oxidation state of $+4$.
$2$. The ligand $ethylenediamine$ $(en)$ is a neutral bidentate ligand. Since there are two $en$ ligands,the total charge contribution is $0$.
$3$. The ligand $thiocyanato$ $(SCN^-)$ is an anionic ligand with a charge of $-1$. Since there are two $SCN$ ligands,the total charge contribution is $-2$.
$4$. The overall charge on the complex is calculated as: $x + 2(0) + 2(-1) = 	ext{Charge}$.
$5$. For $Pt(IV)$,the charge is $+4 + 0 - 2 = +2$.
$6$. Thus,the formula is $[Pt(en)_2(SCN)_2]^{2+}$.

Identify the formula of the coordination complex $Bis(\text{ethylenediamine})dithiocyanatoplatinum(IV)$.

Similar Questions

The compound in which nickel has the lowest oxidation state is

What is the oxidation number of iron in the compound $[Fe(H_2O)_5(NO)]SO_4$?

The $IUPAC$ name of the complex $[Pt(NH_3)_3Br(NO_2)Cl]Cl$ is

The $IUPAC$ name of $[Co(NH_3)_3(H_2O)_2Cl]Cl_2$ is:

The formula of dichlorobis(urea)copper$(II)$ is ........

Vedclass Test Series

Exam Paper Generator

Online Exam Module