Identify the number of unpaired electrons pre | vedclass

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(D) $1$. The central metal ion is $Co^{3+}$. The atomic number of $Co$ is $27$, so the electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.$2$. $NH_3

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$0$, octahedral

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(D) $1$. The central metal ion is $Co^{3+}$. The atomic number of $Co$ is $27$, so the electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.$2$. $NH_3$ is a strong field ligand, which causes pairing of electrons in the $3d$ orbitals.$3$. In the presence of $NH_3$, the six $3d$ electrons pair up in the first three $3d$ orbitals, leaving no unpaired electrons $(n = 0)$.$4$. The hybridization is $d^2sp^3$, which corresponds to an octahedral geometry.

Identify the number of unpaired electrons present and the geometry of the $[Co(NH_3)_6]^{3+}$ complex, respectively.

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