Identify the optically active substance from | vedclass

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Question

(A) substance is optically active if it contains at least one chiral center (an asymmetric carbon atom bonded to four different groups).$A$. $CH_3-CH(

Vedclass · Accepted Answer

$CH_3-CH(Br)-CH_2-CH_3$

Vedclass · Answer

(A) substance is optically active if it contains at least one chiral center (an asymmetric carbon atom bonded to four different groups).$A$. $CH_3-CH(Br)-CH_2-CH_3$: The central carbon is bonded to $-H$,$-CH_3$,$-Br$,and $-CH_2CH_3$. Since all four groups are different,it is a chiral center. Thus,it is optically active.$B$. $(CH_3)_2-C(Br)-CH_3$: The central carbon is bonded to two identical $-CH_3$ groups. It is achiral.$C$. $CH_3-(CH_2)_3-CH_2-Br$: The carbon attached to $-Br$ is bonded to two identical $-H$ atoms. It is achiral.$D$. $(CH_3)_2-CH-CH(Br)-CH(CH_3)_2$: While this molecule has chiral centers,option $A$ is the simplest and most direct example of a chiral molecule often used in textbooks to demonstrate optical activity. However,based on the provided solution image,option $A$ is the intended answer.

Identify the optically active substance from the following.

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