Identify the pair of elements in which the nu | vedclass

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(D) $1. Fe$ electronic configuration: $[Ar] 3d^6 4s^2$. The $(n-1)$ shell is $3d$,which has $6$ electrons.$2. Mn$ electronic configuration: $[Ar] 3d^5

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$Mn, Cr$

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(D) $1. Fe$ electronic configuration: $[Ar] 3d^6 4s^2$. The $(n-1)$ shell is $3d$,which has $6$ electrons.$2. Mn$ electronic configuration: $[Ar] 3d^5 4s^2$. The $(n-1)$ shell is $3d$,which has $5$ electrons.$3. Zn$ electronic configuration: $[Ar] 3d^{10} 4s^2$. The $(n-1)$ shell is $3d$,which has $10$ electrons.$4. Sc$ electronic configuration: $[Ar] 3d^1 4s^2$. The $(n-1)$ shell is $3d$,which has $1$ electron.$5. K$ electronic configuration: $[Ar] 4s^1$. The $(n-1)$ shell is $3s^2 3p^6$,which has $8$ electrons.$6. Cr$ electronic configuration: $[Ar] 3d^5 4s^1$. The $(n-1)$ shell is $3d$,which has $5$ electrons.Comparing the options:$A. Fe (6), Mn (5)$$B. Zn (10), Fe (6)$$C. K (8), Sc (1)$$D. Mn (5), Cr (5)$Thus,$Mn$ and $Cr$ have the same number of electrons in the $(n-1)$ shell.

Identify the pair of elements in which the number of electrons in the $(n-1)$ shell is the same.

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