The correct order of atomic/ionic radii is

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Question

(A) In the $3d$-series,atomic radii generally decrease from $Sc$ to $Cr$ due to the increase in effective nuclear charge. Thus,the order $Sc > Ti > V

Vedclass · Accepted Answer

$Sc > Ti > V > Cr$

Vedclass · Answer

(A) In the $3d$-series,atomic radii generally decrease from $Sc$ to $Cr$ due to the increase in effective nuclear charge. Thus,the order $Sc > Ti > V > Cr$ is correct.For option $(b)$,the correct order is $Zn > Cu > Co \approx Ni$ because the increase in shielding effect balances the increase in nuclear charge.For option $(c)$,for isoelectronic species,the ionic radius increases as the negative charge increases and decreases as the atomic number increases. The correct order is $N^{3-} > O^{2-} > F^{-} > S^{2-} > Cl^{-}$.Therefore,option $(a)$ is the correct statement.

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