Identify the product of the following reaction: $CH_3-CH=CH-CH_2-C \equiv N \xrightarrow[H_3O^{+}]{\text{DIBAL-H}} \text{Product}$

If the enolate ion combines with the carbonyl group of an ester,we get:

$OCH-CHO \xrightarrow{OH^{-}} HOCH_2-COO^-$. The reaction given is:

Following compounds are given:
$(i) CH_3-CH_2-OH$
$(ii) CH_3-CO-CH_3$
$(iii) CH_3-CH(OH)-CH_3$
$(iv) CH_3-OH$
Which of the above compound$(s)$,on being warmed with iodine solution and $NaOH$,will give iodoform?

Which is not true about acetophenone?

Upon treatment with $I_{2}$ and aqueous $NaOH$, which of the following compounds will form iodoform?