Identify the reactions in which N_2 is libera | vedclass

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Question

(C) $(a) \ (NH_4)_2SO_4 + 2NaOH \rightarrow Na_2SO_4 + 2NH_3 + 2H_2O$ (No $N_2$ gas)$(b) \ 8NH_3 + 3Cl_2 \rightarrow N_2 + 6NH_4Cl$ ($N_2$ is liberate

Vedclass · Accepted Answer

$b, c, e$

Vedclass · Answer

(C) $(a) \ (NH_4)_2SO_4 + 2NaOH \rightarrow Na_2SO_4 + 2NH_3 + 2H_2O$ (No $N_2$ gas)$(b) \ 8NH_3 + 3Cl_2 \rightarrow N_2 + 6NH_4Cl$ ($N_2$ is liberated when $NH_3$ is in excess)$(c) \ (NH_4)_2Cr_2O_7 \xrightarrow{\Delta} N_2 + 4H_2O + Cr_2O_3$ ($N_2$ is liberated)$(d) \ NH_4NO_3 \xrightarrow{\Delta} N_2O + 2H_2O$ (No $N_2$ gas)$(e) \ NH_4Cl_{(aq)} + NaNO_{2_{(aq)}} \xrightarrow{\Delta} NaCl + N_2 + 2H_2O$ ($N_2$ is liberated)Thus, the reactions that liberate $N_2$ are $b, c, e$.

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