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(C) Dipole moment $\mu = q 	imes d$.The dipole moments of the given molecules are as follows:$HF = 1.82 \ D$$H_2O = 1.85 \ D$$NH_3 = 1.47 \ D$$HCl =

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$H_2S > HCl > HF$

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(C) Dipole moment $\mu = q 	imes d$.The dipole moments of the given molecules are as follows:$HF = 1.82 \ D$$H_2O = 1.85 \ D$$NH_3 = 1.47 \ D$$HCl = 1.08 \ D$$H_2S = 0.95 \ D$$NF_3 = 0.24 \ D$$HBr = 0.83 \ D$$CO_2 = 0.00 \ D$$BF_3 = 0.00 \ D$Evaluating the options:Option $A$: $1.82 > 1.08 > 0.83$ (Correct order).Option $B$: $1.85 > 0.95 > 0.00$ (Correct order).Option $C$: $0.95 > 1.08 > 1.82$ (Incorrect order,as $HF$ has the highest dipole moment).Option $D$: $1.47 > 0.24 > 0.00$ (Correct order).

Identify the set of molecules which are not in the correct order of their dipole moments.

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