Identify the wrong statement regarding copper | vedclass

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(B) $1$. $CuSO_4$ reacts with $KI$ to form $Cu_2I_2$ and $I_2$ $(2Cu^{2+} + 4I^- \rightarrow Cu_2I_2 + I_2)$. This is a correct statement.$2$. $CuSO_4

Vedclass · Accepted Answer

It reacts with $KCl$ to give $Cl_2$.

Vedclass · Answer

(B) $1$. $CuSO_4$ reacts with $KI$ to form $Cu_2I_2$ and $I_2$ $(2Cu^{2+} + 4I^- \rightarrow Cu_2I_2 + I_2)$. This is a correct statement.$2$. $CuSO_4$ does not react with $KCl$ to produce $Cl_2$ because $Cl^-$ is not a strong enough reducing agent to reduce $Cu^{2+}$ to $Cu^+$. This is the wrong statement.$3$. On strong heating,$CuSO_4 \cdot 5H_2O$ loses water and eventually decomposes to $CuO$ and $SO_3$. This is a correct statement.$4$. The tartrate complex of copper$(II)$ (Fehling's solution) reacts with glucose (an aldehyde) in the presence of $NaOH$ to form a red precipitate of cuprous oxide $(Cu_2O)$. This is a correct statement.

Identify the wrong statement regarding copper$(II)$ sulphate $(CuSO_4)$.

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