Identify the wrongly matched pair.Molecule qu | vedclass

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Question

(B) $1$. $NH_3$: The central atom $N$ has $3$ bond pairs and $1$ lone pair,resulting in a trigonal pyramidal shape.$2$. $PCl_5$: The central atom $P$

Vedclass · Accepted Answer

$PCl_5$ $\quad$ $\quad$ Trigonal planar

Vedclass · Answer

(B) $1$. $NH_3$: The central atom $N$ has $3$ bond pairs and $1$ lone pair,resulting in a trigonal pyramidal shape.$2$. $PCl_5$: The central atom $P$ has $5$ bond pairs and $0$ lone pairs,resulting in a trigonal bipyramidal geometry.$3$. $SF_6$: The central atom $S$ has $6$ bond pairs and $0$ lone pairs,resulting in an octahedral geometry.$4$. $BeCl_2$: The central atom $Be$ has $2$ bond pairs and $0$ lone pairs,resulting in a linear geometry.Therefore,the pair $PCl_5$ - Trigonal planar is incorrectly matched,as it should be trigonal bipyramidal.

List-$I$	List-$II$
$a. NH_3$	$i$. Square pyramidal
$b. ClF_3$	$ii$. Trigonal bipyramidal
$c. PCl_5$	$iii$. Trigonal pyramidal
$d. BrF_5$	$iv$. $T$-shape

List-$I$	List-$II$
$(P)$ $XeF_2$	$(5)$ Trigonal bipyramidal and three lone pairs of electrons
$(Q)$ $XeF_4$	$(3)$ Square planar and two lone pairs of electrons
$(R)$ $XeO_3$	$(2)$ Pyramidal and one lone pair of electrons
$(S)$ $XeO_3F_2$	$(4)$ Trigonal bipyramidal and no lone pairs of electrons

Identify the wrongly matched pair.
Molecule $\quad$ $\quad$ Shape or geometry of molecule

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If $AB_{4}$ molecule is a polar molecule,a possible geometry of $AB_{4}$ is :

Match List-$I$ with List-$II$ :
List-$I$ List-$II$
$a. NH_3$ $i$. Square pyramidal
$b. ClF_3$ $ii$. Trigonal bipyramidal
$c. PCl_5$ $iii$. Trigonal pyramidal
$d. BrF_5$ $iv$. $T$-shape

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Identify the wrongly matched pair.Molecule $\quad$ $\quad$ Shape or geometry of molecule