Identify the wrong statement for the followin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Reaction $A$ is an electrophilic addition of $HBr$ to $3$-methyl-$1$-butene,which involves a $1,2$-hydride shift to form a more stable $3^\circ$ c

Vedclass · Accepted Answer

$A$ and $C$ both products are saturated compounds.

Vedclass · Answer

(B) Reaction $A$ is an electrophilic addition of $HBr$ to $3$-methyl-$1$-butene,which involves a $1,2$-hydride shift to form a more stable $3^\circ$ carbocation,resulting in $2$-bromo-$2$-methylbutane ($3^\circ$ halide,saturated).Reaction $B$ is a free radical addition of $HBr$ in the presence of peroxide (Anti-Markovnikov),forming $1$-bromo-$3$-methylbutane ($1^\circ$ halide,saturated).Reaction $C$ is an allylic bromination using $NBS$,which follows a free radical substitution mechanism to form $3$-bromo-$3$-methyl-$1$-butene ($3^\circ$ halide,unsaturated).Since $C$ is an unsaturated compound (contains a double bond),statement $(b)$ is incorrect.

Identify the wrong statement for the following reactions:
$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{HBr} A$
$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{HBr + ROOR} B$
$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{NBS} C$

Similar Questions

Ethyl phenyl acetylene ($1$-phenyl-but-$1$-yne) on reduction with partially deactivated palladised charcoal (Lindlar's catalyst) gives:

The reaction of $HBr$ with $CH_3-C(CH_3)=CH_2$ in the presence of peroxide will give:

In which of the following reactions does the product contain a chiral center?

One mole of each of the following alkenes is catalytically hydrogenated. The quantity of heat evolved will be the lowest in the case of

Which of the following catalysts is used to convert an alkyne $(-C \equiv C-)$ to form a $cis$-alkene?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify the wrong statement for the following reactions:$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{HBr} A$$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{HBr + ROOR} B$$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{NBS} C$