The reaction of HBr with CH_3-C(CH_3)=CH_2 in | vedclass

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Question

(C) In the presence of peroxide,the addition of $HBr$ to an unsymmetrical alkene follows the Anti-Markovnikov rule (also known as the Kharasch effect)

Vedclass · Accepted Answer

$CH_3-CH(CH_3)-CH_2Br$

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(C) In the presence of peroxide,the addition of $HBr$ to an unsymmetrical alkene follows the Anti-Markovnikov rule (also known as the Kharasch effect).In this reaction,the bromine atom attaches to the carbon atom of the double bond that has more hydrogen atoms.Reaction: $CH_3-C(CH_3)=CH_2 + HBr \xrightarrow{	ext{Peroxide}} CH_3-CH(CH_3)-CH_2Br$.

The reaction of $HBr$ with $CH_3-C(CH_3)=CH_2$ in the presence of peroxide will give:

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