If $\tan^{-1} (x^2 + 3|x|-4) = \tan^{-1} (4\pi + \sin^{-1}(\sin 14))$,then the value of $\cos^{-1}(\cos 3|x|)$ is equal to

  • A
    $3\pi - 9$
  • B
    $4\pi - 9$
  • C
    $9$
  • D
    $9 - 2\pi$

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