If 4x + 5y = 83 and frac{3x}{2y} = frac{21}{2 | vedclass

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(B) Given equations are:$4x + 5y = 83$ ....$(1)$$\frac{3x}{2y} = \frac{21}{22}$ ....$(2)$From equation $(2)$,we can simplify the ratio:$\frac{x}{y} =

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$4$

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(B) Given equations are:$4x + 5y = 83$ ....$(1)$$\frac{3x}{2y} = \frac{21}{22}$ ....$(2)$From equation $(2)$,we can simplify the ratio:$\frac{x}{y} = \frac{21}{22} 	imes \frac{2}{3} = \frac{7}{11}$So,$x = \frac{7}{11}y$.Substitute $x = \frac{7}{11}y$ into equation $(1)$:$4(\frac{7}{11}y) + 5y = 83$$\frac{28}{11}y + 5y = 83$$(\frac{28 + 55}{11})y = 83$$\frac{83}{11}y = 83$$y = 11$Now,find $x$ using $x = \frac{7}{11}y$:$x = \frac{7}{11} 	imes 11 = 7$Finally,calculate $y - x$:$y - x = 11 - 7 = 4$

If $4x + 5y = 83$ and $\frac{3x}{2y} = \frac{21}{22}$,then $y - x = ?$

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