If a and b are rational numbers and (a-1) sqr | vedclass

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(D) Given the equation: $(a-1) \sqrt{2} + 3 = b \sqrt{2} + a$.Since $a$ and $b$ are rational numbers,we can equate the rational and irrational parts o

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$5$

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(D) Given the equation: $(a-1) \sqrt{2} + 3 = b \sqrt{2} + a$.Since $a$ and $b$ are rational numbers,we can equate the rational and irrational parts on both sides of the equation.The rational part on the left is $3$ and on the right is $a$. Therefore,$a = 3$.The coefficient of the irrational part $\sqrt{2}$ on the left is $(a-1)$ and on the right is $b$. Therefore,$a - 1 = b$.Substituting $a = 3$ into the second equation: $3 - 1 = b$,which gives $b = 2$.Finally,the value of $(a+b) = 3 + 2 = 5$.

If $a$ and $b$ are rational numbers and $(a-1) \sqrt{2} + 3 = b \sqrt{2} + a$,then the value of $(a+b)$ is

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