If P(A) = 2/3,P(B) = 1/2 and P(A cup B) = 5/6 | vedclass

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(C) The formula for the union of two events is $P(A \cup B) = P(A) + P(B) - P(A \cap B)$.Substituting the given values: $5/6 = 2/3 + 1/2 - P(A \cap B)

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Independent

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(C) The formula for the union of two events is $P(A \cup B) = P(A) + P(B) - P(A \cap B)$.Substituting the given values: $5/6 = 2/3 + 1/2 - P(A \cap B)$.$5/6 = 4/6 + 3/6 - P(A \cap B)$.$5/6 = 7/6 - P(A \cap B)$.$P(A \cap B) = 7/6 - 5/6 = 2/6 = 1/3$.Since $P(A \cap B) 
eq 0$,the events are not mutually exclusive.Now,check for independence: $P(A) 	imes P(B) = (2/3) 	imes (1/2) = 1/3$.Since $P(A \cap B) = P(A) 	imes P(B) = 1/3$,the events $A$ and $B$ are independent.

If $P(A) = 2/3$,$P(B) = 1/2$ and $P(A \cup B) = 5/6$,then events $A$ and $B$ are

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