If a and b are odd integers,then the roots of | vedclass

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(A) The given quadratic equation is $2ax^2 + (2a + b)x + b = 0$,where $a 
e 0$.The discriminant $D$ of a quadratic equation $Ax^2 + Bx + C = 0$ is gi

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(A) The given quadratic equation is $2ax^2 + (2a + b)x + b = 0$,where $a 
e 0$.The discriminant $D$ of a quadratic equation $Ax^2 + Bx + C = 0$ is given by $D = B^2 - 4AC$.Here,$A = 2a$,$B = (2a + b)$,and $C = b$.Substituting these values into the formula for $D$:$D = (2a + b)^2 - 4(2a)(b)$$D = 4a^2 + 4ab + b^2 - 8ab$$D = 4a^2 - 4ab + b^2$$D = (2a - b)^2$Since $a$ and $b$ are integers,$(2a - b)^2$ is a perfect square of an integer.For a quadratic equation with rational coefficients,if the discriminant $D$ is a perfect square,the roots are always rational.Therefore,the roots of the given equation are rational.

If $a$ and $b$ are odd integers,then the roots of the equation $2ax^2 + (2a + b)x + b = 0, a \ne 0,$ will be

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