(C) Given that $A \subseteq B$,which means every element of set $A$ is also an element of set $B$.Therefore,the union of sets $A$ and $B$ is equal to

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(C) Given that $A \subseteq B$,which means every element of set $A$ is also an element of set $B$.Therefore,the union of sets $A$ and $B$ is equal to set $B$,i.e.,$A \cup B = B$.Consequently,the number of elements in $A \cup B$ is equal to the number of elements in $B$.$n(A \cup B) = n(B) = 6$.

Competitive Quantitative Aptitude Algebra Set Theory

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If $n(A) = 3$,$n(B) = 6$ and $A \subseteq B$,then the number of elements in $A \cup B$ is equal to

A
$3$
B
$9$
C
$6$
D
None of these

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Let $P(n) : 3^n < n!$ for $n \in N$. If this statement is true for all $n \geq \lambda$,then the smallest value of $\lambda$ is:

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Let $A, B$ and $C$ be sets such that $\phi \ne A \cap B \subseteq C$. Then which of the following statements is not true?

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If $n(A) = 3$,$n(B) = 6$ and $A \subseteq B$,then the number of elements in $A \cup B$ is equal to

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