(A) Given that $A \subseteq B$,which means every element of set $A$ is also an element of set $B$. Therefore,the intersection of $A$ and $B$ is simply

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(A) Given that $A \subseteq B$,which means every element of set $A$ is also an element of set $B$. Therefore,the intersection of $A$ and $B$ is simply set $A$,i.e.,$A \cap B = A$. Thus,the number of elements in $A \cap B$ is equal to the number of elements in $A$. $n(A \cap B) = n(A) = 3$.

Competitive Quantitative Aptitude Algebra Set Theory

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If $n(A) = 3$ and $n(B) = 6$ and $A \subseteq B$,then the number of elements in $A \cap B$ is equal to

A
$3$
B
$9$
C
$6$
D
None of these

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If $n(A) = 3$ and $n(B) = 6$ and $A \subseteq B$,then the number of elements in $A \cap B$ is equal to

Similar Questions

If $A$ and $B$ are two sets,then $A \times B = B \times A$ if and only if

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