If cos theta - sin theta = sqrt{2} sin theta, | vedclass

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(A) Given: $\cos 	heta - \sin 	heta = \sqrt{2} \sin 	heta$Rearranging the terms,we get: $\cos 	heta = \sqrt{2} \sin 	heta + \sin 	heta$$\cos 	h

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$\sqrt{2} \cos 	heta$

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(A) Given: $\cos 	heta - \sin 	heta = \sqrt{2} \sin 	heta$Rearranging the terms,we get: $\cos 	heta = \sqrt{2} \sin 	heta + \sin 	heta$$\cos 	heta = (\sqrt{2} + 1) \sin 	heta$To isolate $\sin 	heta$,multiply both sides by $(\sqrt{2} - 1)$:$(\sqrt{2} - 1) \cos 	heta = (\sqrt{2} - 1)(\sqrt{2} + 1) \sin 	heta$$(\sqrt{2} - 1) \cos 	heta = (2 - 1) \sin 	heta$$\sqrt{2} \cos 	heta - \cos 	heta = \sin 	heta$Rearranging to find $\cos 	heta + \sin 	heta$:$\cos 	heta + \sin 	heta = \sqrt{2} \cos 	heta$

If $\cos \theta - \sin \theta = \sqrt{2} \sin \theta$,then $\cos \theta + \sin \theta$ is equal to

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