If tan theta = frac{x sin phi}{1 - x cos phi} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given $	an 	heta = \frac{x \sin \phi}{1 - x \cos \phi}$.Rearranging,we get $x \sin \phi = 	an 	heta - x \cos \phi 	an 	heta$.$x(\sin \phi +

Vedclass · Accepted Answer

$\frac{\sin 	heta}{\sin \phi}$

Vedclass · Answer

(B) Given $	an 	heta = \frac{x \sin \phi}{1 - x \cos \phi}$.Rearranging,we get $x \sin \phi = 	an 	heta - x \cos \phi 	an 	heta$.$x(\sin \phi + \cos \phi 	an 	heta) = 	an 	heta$.$x \left( \sin \phi + \cos \phi \frac{\sin 	heta}{\cos 	heta} ight) = \frac{\sin 	heta}{\cos 	heta}$.$x \left( \frac{\sin \phi \cos 	heta + \cos \phi \sin 	heta}{\cos 	heta} ight) = \frac{\sin 	heta}{\cos 	heta}$.$x \sin(	heta + \phi) = \sin 	heta \Rightarrow x = \frac{\sin 	heta}{\sin(	heta + \phi)}$.Similarly,for $	an \phi = \frac{y \sin 	heta}{1 - y \cos 	heta}$,we get $y = \frac{\sin \phi}{\sin(	heta + \phi)}$.Therefore,$\frac{x}{y} = \frac{\sin 	heta / \sin(	heta + \phi)}{\sin \phi / \sin(	heta + \phi)} = \frac{\sin 	heta}{\sin \phi}$.

If $\tan \theta = \frac{x \sin \phi}{1 - x \cos \phi}$ and $\tan \phi = \frac{y \sin \theta}{1 - y \cos \theta}$,then $\frac{x}{y} = $

Similar Questions

If $\sin \theta = -\frac{4}{5}$ and $\theta$ lies in the third quadrant,then $\cos \frac{\theta}{2} = $

The value of $\sin ^{2} 75^{\circ}-\sin ^{2} 15^{\circ}$ is:

If $x = \cos 10^\circ \cos 20^\circ \cos 40^\circ ,$ then the value of $x$ is

If $x = r \cos \theta \cos \phi$,$y = r \cos \theta \sin \phi$,and $z = r \sin \theta$,then the value of $x^{2} + y^{2} + z^{2}$ is

If $5 \cos \theta + 12 \sin \theta = 13,$ then $\tan \theta = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module