If 5 cos theta + 12 sin theta = 13, then tan | vedclass

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Question

(C) Given equation: $5 \cos 	heta + 12 \sin 	heta = 13$Divide both sides by $13$:$\frac{5}{13} \cos 	heta + \frac{12}{13} \sin 	heta = 1$Let $\cos

Vedclass · Accepted Answer

$\frac{12}{5}$

Vedclass · Answer

(C) Given equation: $5 \cos 	heta + 12 \sin 	heta = 13$Divide both sides by $13$:$\frac{5}{13} \cos 	heta + \frac{12}{13} \sin 	heta = 1$Let $\cos \alpha = \frac{5}{13}$ and $\sin \alpha = \frac{12}{13}$. Then $	an \alpha = \frac{12}{5}$.The equation becomes $\cos \alpha \cos 	heta + \sin \alpha \sin 	heta = 1$$\cos(	heta - \alpha) = 1$This implies $	heta - \alpha = 0$,so $	heta = \alpha$.Therefore,$	an 	heta = 	an \alpha = \frac{12}{5}$.

If $5 \cos \theta + 12 \sin \theta = 13,$ then $\tan \theta = ?$

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