If $(\sec A + \tan A)(\sec B + \tan B)(\sec C + \tan C) = (\sec A - \tan A)(\sec B - \tan B)(\sec C - \tan C),$ then each side is equal to

  • A
    $1$
  • B
    $-1$
  • C
    $0$
  • D
    $1$ or $-1$

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